Ijumaa, 17 Aprili 2015

Jumatano, 25 Machi 2015

LIGHT PARTY 1. EX1

Solve the following question below.

1.(a)What is meant by the principal focus of a converging lens?

   (b)What happens to the image of an object placed between the principal focus and a converging lens? Illustrate your answer by using a ray diagram.

   (c) An object 4cm high is placed 20cm from a converging lens of focal length 8cm:
    Determine:
   (i)the distance of the image    from the lens.
   (ii)the magnification.
   (iii)the height of the image.

2.(a) (i)What is meant by the term real image of a convex lens.
    (ii)Give two differences between images formed in a plane mirror and a pin hole camera.

   (b) (i)Define the principal focus in terms of a convex lens.
         (ii)Draw a sketch diagram to show position of an object and image in a concave mirror such that the image is virtual.

   (c)An object is placed 20cm from a concave mirror of unknown focal length. A real image is formed whose height is twice the height of the object. Calculate the position of the image and focal length of the mirror.

3.(a) State briefly:
     (i) The cause of refraction of light when passing through transparent media.
     (ii) Position of image in a concave mirror, of a very distant object.
     (iii) Cause for a blurred image in a concave mirror or a convex lenses.

  (b)Explain the following:
     (i) Condition giving rise to critical angle and total internal reflection.
     (ii) Two principal in physics used to make telescope.

  (c) A telescope of 5m diameter reflector of a focal length 18m is used to focus the image of the sun . Using the distance of the sun from the earth and diameter of the sun as 1.5 ×10^11m and 1.4 ×10^9m respectively , calculate the:
   (i) Position of the image of the sun.
   (ii) Diameter of the image of the sun.